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	bpf: do not use reciprocal divide
At first Jakub Zawadzki noticed that some divisions by reciprocal_divide were not correct. (off by one in some cases) http://www.wireshark.org/~darkjames/reciprocal-buggy.c He could also show this with BPF: http://www.wireshark.org/~darkjames/set-and-dump-filter-k-bug.c The reciprocal divide in linux kernel is not generic enough, lets remove its use in BPF, as it is not worth the pain with current cpus. Signed-off-by: Eric Dumazet <edumazet@google.com> Reported-by: Jakub Zawadzki <darkjames-ws@darkjames.pl> Cc: Mircea Gherzan <mgherzan@gmail.com> Cc: Daniel Borkmann <dxchgb@gmail.com> Cc: Hannes Frederic Sowa <hannes@stressinduktion.org> Cc: Matt Evans <matt@ozlabs.org> Cc: Martin Schwidefsky <schwidefsky@de.ibm.com> Cc: Heiko Carstens <heiko.carstens@de.ibm.com> Cc: David S. Miller <davem@davemloft.net> Signed-off-by: David S. Miller <davem@davemloft.net>
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					 6 changed files with 45 additions and 46 deletions
				
			
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			@ -641,10 +641,10 @@ static int build_body(struct jit_ctx *ctx)
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			emit(ARM_MUL(r_A, r_A, r_X), ctx);
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			break;
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		case BPF_S_ALU_DIV_K:
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			/* current k == reciprocal_value(userspace k) */
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			if (k == 1)
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				break;
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			emit_mov_i(r_scratch, k, ctx);
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			/* A = top 32 bits of the product */
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			emit(ARM_UMULL(r_scratch, r_A, r_A, r_scratch), ctx);
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			emit_udiv(r_A, r_A, r_scratch, ctx);
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			break;
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		case BPF_S_ALU_DIV_X:
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			update_on_xread(ctx);
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			@ -223,10 +223,11 @@ static int bpf_jit_build_body(struct sk_filter *fp, u32 *image,
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			}
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			PPC_DIVWU(r_A, r_A, r_X);
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			break;
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		case BPF_S_ALU_DIV_K: /* A = reciprocal_divide(A, K); */
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		case BPF_S_ALU_DIV_K: /* A /= K */
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			if (K == 1)
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				break;
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			PPC_LI32(r_scratch1, K);
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			/* Top 32 bits of 64bit result -> A */
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			PPC_MULHWU(r_A, r_A, r_scratch1);
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			PPC_DIVWU(r_A, r_A, r_scratch1);
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			break;
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		case BPF_S_ALU_AND_X:
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			ctx->seen |= SEEN_XREG;
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			@ -371,11 +371,13 @@ static int bpf_jit_insn(struct bpf_jit *jit, struct sock_filter *filter,
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		/* dr %r4,%r12 */
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		EMIT2(0x1d4c);
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		break;
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	case BPF_S_ALU_DIV_K: /* A = reciprocal_divide(A, K) */
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		/* m %r4,<d(K)>(%r13) */
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		EMIT4_DISP(0x5c40d000, EMIT_CONST(K));
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		/* lr %r5,%r4 */
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		EMIT2(0x1854);
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	case BPF_S_ALU_DIV_K: /* A /= K */
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		if (K == 1)
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			break;
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		/* lhi %r4,0 */
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		EMIT4(0xa7480000);
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		/* d %r4,<d(K)>(%r13) */
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		EMIT4_DISP(0x5d40d000, EMIT_CONST(K));
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		break;
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	case BPF_S_ALU_MOD_X: /* A %= X */
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		jit->seen |= SEEN_XREG | SEEN_RET0;
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			@ -391,6 +393,11 @@ static int bpf_jit_insn(struct bpf_jit *jit, struct sock_filter *filter,
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		EMIT2(0x1854);
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		break;
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	case BPF_S_ALU_MOD_K: /* A %= K */
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		if (K == 1) {
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			/* lhi %r5,0 */
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			EMIT4(0xa7580000);
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			break;
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		}
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		/* lhi %r4,0 */
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		EMIT4(0xa7480000);
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		/* d %r4,<d(K)>(%r13) */
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			@ -497,9 +497,20 @@ void bpf_jit_compile(struct sk_filter *fp)
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			case BPF_S_ALU_MUL_K:	/* A *= K */
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				emit_alu_K(MUL, K);
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				break;
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			case BPF_S_ALU_DIV_K:	/* A /= K */
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				emit_alu_K(MUL, K);
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				emit_read_y(r_A);
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			case BPF_S_ALU_DIV_K:	/* A /= K with K != 0*/
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				if (K == 1)
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					break;
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				emit_write_y(G0);
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#ifdef CONFIG_SPARC32
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				/* The Sparc v8 architecture requires
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				 * three instructions between a %y
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				 * register write and the first use.
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				 */
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				emit_nop();
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				emit_nop();
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				emit_nop();
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#endif
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				emit_alu_K(DIV, K);
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				break;
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			case BPF_S_ALU_DIV_X:	/* A /= X; */
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				emit_cmpi(r_X, 0);
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			@ -359,15 +359,21 @@ void bpf_jit_compile(struct sk_filter *fp)
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				EMIT2(0x89, 0xd0);	/* mov %edx,%eax */
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				break;
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			case BPF_S_ALU_MOD_K: /* A %= K; */
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				if (K == 1) {
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					CLEAR_A();
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					break;
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				}
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				EMIT2(0x31, 0xd2);	/* xor %edx,%edx */
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				EMIT1(0xb9);EMIT(K, 4);	/* mov imm32,%ecx */
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				EMIT2(0xf7, 0xf1);	/* div %ecx */
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				EMIT2(0x89, 0xd0);	/* mov %edx,%eax */
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				break;
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			case BPF_S_ALU_DIV_K: /* A = reciprocal_divide(A, K); */
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				EMIT3(0x48, 0x69, 0xc0); /* imul imm32,%rax,%rax */
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				EMIT(K, 4);
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				EMIT4(0x48, 0xc1, 0xe8, 0x20); /* shr $0x20,%rax */
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			case BPF_S_ALU_DIV_K: /* A /= K */
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				if (K == 1)
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					break;
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				EMIT2(0x31, 0xd2);	/* xor %edx,%edx */
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				EMIT1(0xb9);EMIT(K, 4);	/* mov imm32,%ecx */
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				EMIT2(0xf7, 0xf1);	/* div %ecx */
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				break;
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			case BPF_S_ALU_AND_X:
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				seen |= SEEN_XREG;
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			@ -36,7 +36,6 @@
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#include <asm/uaccess.h>
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#include <asm/unaligned.h>
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#include <linux/filter.h>
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#include <linux/reciprocal_div.h>
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#include <linux/ratelimit.h>
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#include <linux/seccomp.h>
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#include <linux/if_vlan.h>
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			@ -166,7 +165,7 @@ unsigned int sk_run_filter(const struct sk_buff *skb,
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			A /= X;
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			continue;
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		case BPF_S_ALU_DIV_K:
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			A = reciprocal_divide(A, K);
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			A /= K;
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			continue;
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		case BPF_S_ALU_MOD_X:
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			if (X == 0)
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			@ -553,11 +552,6 @@ int sk_chk_filter(struct sock_filter *filter, unsigned int flen)
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		/* Some instructions need special checks */
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		switch (code) {
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		case BPF_S_ALU_DIV_K:
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			/* check for division by zero */
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			if (ftest->k == 0)
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				return -EINVAL;
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			ftest->k = reciprocal_value(ftest->k);
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			break;
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		case BPF_S_ALU_MOD_K:
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			/* check for division by zero */
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			if (ftest->k == 0)
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			@ -853,27 +847,7 @@ void sk_decode_filter(struct sock_filter *filt, struct sock_filter *to)
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	to->code = decodes[code];
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	to->jt = filt->jt;
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	to->jf = filt->jf;
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	if (code == BPF_S_ALU_DIV_K) {
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		/*
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		 * When loaded this rule user gave us X, which was
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		 * translated into R = r(X). Now we calculate the
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		 * RR = r(R) and report it back. If next time this
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		 * value is loaded and RRR = r(RR) is calculated
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		 * then the R == RRR will be true.
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		 *
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		 * One exception. X == 1 translates into R == 0 and
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		 * we can't calculate RR out of it with r().
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		 */
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		if (filt->k == 0)
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			to->k = 1;
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		else
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			to->k = reciprocal_value(filt->k);
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		BUG_ON(reciprocal_value(to->k) != filt->k);
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	} else
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		to->k = filt->k;
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	to->k = filt->k;
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}
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int sk_get_filter(struct sock *sk, struct sock_filter __user *ubuf, unsigned int len)
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